Как распечатать имена вложенных функций?

Взял ответ из этого примера:

import ast, inspect

# this is the test scenario
def function1():
    f1_var1 = 42
    def function2():
        f2_var1 = 42
        f2_var2 = 42
        def function3():
            f3_var1 = 42

# derive source code for top-level function
src = inspect.getsource(function1)

# derive abstract syntax tree rooted at top-level function
node = ast.parse(src)

# next, ast's walk method takes all the difficulty out of tree-traversal for us
for x in ast.walk(node):
    # functions have names whereas variables have ids,
    # nested-classes may all use different terminology
    # you'll have to look at the various node-types to
    # get this part exactly right
    name_or_id = getattr(x,'name', getattr(x,'id',None))
    if name_or_id:
        print name_or_id

Ответ:

function1
function2
f1_var1
function3
f2_var1
f2_var2
f3_var1

Спасибо!

Используя функциональность, предоставляемую модулем ast, мы можем получить требуемый результат следующим образом:

from ast import parse, walk, FunctionDef
from inspect import getsource

def function_one():
    print("Function one")
    def function_two():
        print("Function two")
        def function_three():
            print("Function three")

def getfuncs(func): 
    for n in walk(parse(getsource(func))):
        if isinstance(n, FunctionDef):
            yield n.name

print("(" + ", ".join(getfuncs(function_one)) + ")")

Выход:

(function_one, function_two, function_three)