Последовательности подсчета HoW в Python

Пытаться:

import pandas as pd
from itertools import groupby


out = {}
for k, g in groupby(Responses):
    if k == 'S':
        l = sum(1 for _ in g)
        out[l] = out.get(l, 0) + 1

df = pd.DataFrame([{'Sequence': k, 'Frequency': f'{v} times'} for k, v in out.items()]).sort_values('Sequence', ascending=False)
print(df)

Отпечатки:

   Sequence Frequency
5         8   2 times
1         6   2 times
2         4   2 times
4         3   2 times
3         2   2 times
0         1   8 times

Попробуй это:

s = pd.Series(Responses)
s = s.loc[s.eq('S')].groupby(s.ne(s.shift()).cumsum()).count().value_counts()
df = s.map('{} times'.format).rename_axis('Sequence').reset_index(name = 'Frequency')

Выход:

   Sequence Frequency
0         1   8 times
1         6   2 times
2         4   2 times
3         2   2 times
4         3   2 times
5         8   2 times

Использование itertools:

import itertools as it
import pandas as pd

N='N'
S='S'
df = pd.DataFrame({'Responses':[N, N, N, N, N, S, N, N, N, N, N, N, S, N, N, N, N, N, N, N, N, N, N, N, N, N, S, S, S, S, S, S, N, N, S, N, N, N, S, S, S, S, N, S, N, N, N, N, N, N, N, S, S, N, N, N, S, S, S, N, S, S, S, S, S, S, S, S,N, N, N, N, N, S, N, N, N, N, N, N, S, N, N, N, N, N, N, N, N, N, N, N, N, N, S, S, S, S, S, S, N, N, S, N, N, N, S, S, S, S, N, S, N, N, N, N, N, N, N, S, S, N, N, N, S, S, S, N, S, S, S, S, S, S, S, S] })

l = [list(g).count('S') for k, g in it.groupby(df['Responses']) if k=='S']

r = (pd.DataFrame.from_dict({i:l.count(i) for i in range(min(l), max(l)+1)}, 
                            orient='index')
                 .reset_index()
                 )

r.columns=['Sequence', 'Frequency']

print(r)

   Sequence  Frequency
0         1          8
1         2          2
2         3          2
3         4          2
4         5          0
5         6          2
6         7          0
7         8          2