Разделить вариантную строку в python

Вот как бы я это сделал.

Паттерн, который я вижу, заключается в том, что функции всегда попадают между первыми двумя и двумя последними словами.

Я использовал нарезку после разделения каждой строки.

text = """1.20.4.2  script1  get_pool  tim 3.15.08
1.20.5.1  script1  get_aggregate  bob 3.16.10
2.0.4  script2  get_aggregate, get_pool tim 3.16.10
2.0.5  script2  get_aggregate, get_pool, make_volume paul 3.24.10
"""


# Split each line into words after splitting text into lines
tokens = [line.split() for line in text.splitlines()]

LINE = 10 * "*" # For prettier output.

# Use slicing syntax to get first two words [:2]
# All words except first two and last two [2:-2]
# Strip the comma from each word inside a comprehension
# Use slicing syntax to get last two words [-2:]
for (item, name), functions, (owner, date) in [
    (items[:2], [word.strip(",") for word in items[2:-2]], items[-2:])
    for items in tokens
]:
    for message in (
        f"The item, name are {(item, name)}",
        f"The functions are {functions}",
        f"The owner, date are {(owner, date)}",
        LINE,
    ):
        print(message)

ВЫХОД:

The item, name are ('1.20.4.2', 'script1')
The functions are ['get_pool']
The owner, date are ('tim', '3.15.08')
**********
The item, name are ('1.20.5.1', 'script1')
The functions are ['get_aggregate']
The owner, date are ('bob', '3.16.10')
**********
The item, name are ('2.0.4', 'script2')
The functions are ['get_aggregate', 'get_pool']
The owner, date are ('tim', '3.16.10')
**********
The item, name are ('2.0.5', 'script2')
The functions are ['get_aggregate', 'get_pool', 'make_volume']
The owner, date are ('paul', '3.24.10')
**********