Rust: невозможно вернуть значение, ссылающееся на временное значение

Noob в ржавчине здесь, пытается реализовать общую функцию повтора и пытается решить, как устранить ошибку времени жизни:

async fn retry<T, E, Fut, F>(mut f: F, client: &Client, max_retries: i32) -> Result<T, E>
    where
        Fut: Future<Output = Result<T, E>>,
        F: FnMut(&Client) -> Fut,
{
    let mut count = 0;
    loop {
        let result = f(client).await;

        if result.is_ok() {
            break result;
        } else {
            if count > max_retries {
                break result;
            }
            count += 1;
        }
    }
}

и ошибка

| |_________________^ returning this value requires that `'1` must outlive `'2`

error[E0515]: cannot return value referencing temporary value

Как я вызываю метод:

let lambda = &mut move |client: &Client| {
            client
                .download_object(
                    &GetObjectRequest {
                        bucket: some_bucket,
                        object: some_object,
                        ..Default::default()
                    },
                    &Range::default(),
                )
        };
        retry(lambda, &self.client, 5).await

Я не могу понять, что возвращаемое значение f(client).await должно пережить что именно?

Полная ошибка:

error[E0621]: explicit lifetime required in the type of `client`
  --> src/main.rs:35:22
   |
28 | async fn retry<'a, T, E, Fut, F>(mut f: F, client: &Client, max_retries: i32) -> Result<T, E>
   |                                                    ------- help: add explicit lifetime `'a` to the type of `client`: `&'a Client`
...
35 |         let result = f(client).await;
   |                      ^^^^^^^^^ lifetime `'a` required

error: lifetime may not live long enough
  --> src/main.rs:68:13
   |
67 |           let lambda = &mut move |client: &Client| {
   |                                           -      - return type of closure `impl Future<Output = Result<Vec<u8>, google_cloud_storage::http::Error>>` contains a lifetime `'2`
   |                                           |
   |                                           let's call the lifetime of this reference `'1`
68 | /             client
69 | |                 .download_object(
70 | |                     &GetObjectRequest {
71 | |                         bucket: some_bucket,
...  |
75 | |                     &Range::default(),
76 | |                 )
   | |_________________^ returning this value requires that `'1` must outlive `'2`

error[E0515]: cannot return value referencing temporary value
  --> src/main.rs:68:13
   |
68 | /              client
69 | |                  .download_object(
70 | |                      &GetObjectRequest {
   | | ______________________-
71 | ||                         bucket: some_bucket,
72 | ||                         object: some_object,
73 | ||                         ..Default::default()
74 | ||                     },
   | ||_____________________- temporary value created here
75 | |                      &Range::default(),
76 | |                  )
   | |__________________^ returns a value referencing data owned by the current function

error[E0515]: cannot return value referencing temporary value
  --> src/main.rs:68:13
   |
68 | /             client
69 | |                 .download_object(
70 | |                     &GetObjectRequest {
71 | |                         bucket: some_bucket,
...  |
75 | |                     &Range::default(),
   | |                      ---------------- temporary value created here
76 | |                 )
   | |_________________^ returns a value referencing data owned by the current function