web.xml
<?xml version = "1.0" encoding = "UTF-8"?>
<web-app xmlns:xsi = "http://www.w3.org/2001/XMLSchema-instance" xmlns = "http://java.sun.com/xml/ns/javaee"xsi:schemaLocation = "http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version = "3.0">
<display-name>ValidationForm</display-name>
<servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>spring-dispatcher</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> </web-app> spring-dispatcher-servlet.xml <?xml version = "1.0" encoding = "UTF-8"?> <web-app xmlns:xsi = "http://www.w3.org/2001/XMLSchema-instance" xmlns = "http://java.sun.com/xml/ns/javaee" xsi:schemaLocation = "http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version = "3.0">
<display-name> ValidationForm</display-name> <servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> </servlet>
<servlet-mapping>
<servlet-name>spring-dispatcher</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping>
</web-app>
index.jsp
<%@ page language = "java" contentType = "text/html; charset=ISO-8859-1" pageEncoding = "ISO-8859-1"%>
<!DOCTYPE html>
<html>
<head>
<meta charset = "ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<form action = "/wel" method = "post">
name:<input type = "text" name = "name" placeholder = "UserName">
<br> password:<input type = "password" name = "pass" placeholder = "Password">
<br>
<input type = "submit" value = "login">
</form>
</body>
</html>
HomeController.java
package jbr.springmvc.controller;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;
@Controller public class HomeController {
@RequestMapping(value = "demo1/wel", method = RequestMethod.POST)
public ModelAndView hello(HttpServletRequest req,HttpServletResponse res) {
String name=req.getParameter("name");
String pass=req.getParameter("pass");
if (name.equals("mohit")&&pass.equals("admin")) {
String messege = "Welcome"+name;
return new ModelAndView("welcomepage","message",messege);
}
else
{ return new ModelAndView("errorpage","message","Authantication Failed");
}
} }
в этом случае будет показана ошибка 404: ресурс не найден, я действительно не знаю, что случилось с этим, потому что я новичок весной. пожалуйста, помогите ребята. заранее спасибо.
У вас есть welcomepage.jsp?
да, у меня тоже есть приветственная страница и страница с ошибками




Когда я проверил, этот код работает:
Web.xml:
<?xml version = "1.0" encoding = "UTF-8"?>
<web-app xmlns:xsi = "http://www.w3.org/2001/XMLSchema-instance"
xmlns = "http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation = "http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id = "WebApp_ID" version = "3.0">
<display-name>ValidationForm</display-name>
<servlet>
<servlet-name>spring-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring-servlet.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring-dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
Spring-servlet.xml
<?xml version = "1.0" encoding = "UTF-8"?>
<beans:beans xmlns = "http://www.springframework.org/schema/mvc"
xmlns:xsi = "http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans = "http://www.springframework.org/schema/beans"
xmlns:context = "http://www.springframework.org/schema/context"
xsi:schemaLocation = "http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd">
<annotation-driven />
<context:component-scan base-package = "com.demo.spring" />
<beans:bean
class = "org.springframework.web.servlet.view.InternalResourceViewResolver">
<beans:property name = "prefix" value = "/WEB-INF/views/" />
<beans:property name = "suffix" value = ".jsp" />
</beans:bean>
HomeController:
package com.demo.spring.controller;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;
@Controller
public class HomeController {
@RequestMapping(value = "/", method = RequestMethod.GET)
public ModelAndView welcome() {
return new ModelAndView("welcome");
}
@RequestMapping(value = "demo1/wel", method = RequestMethod.POST)
public ModelAndView hello(HttpServletRequest req, HttpServletResponse res) {
String name = req.getParameter("name");
String pass = req.getParameter("pass");
if (name.equals("mohit") && pass.equals("admin")) {
String messege = "Welcome" + name;
return new ModelAndView("welcome", "message", messege);
} else {
return new ModelAndView("errorpage", "message", "Authantication Failed");
}
}
}
Попробуйте использовать это
You need to configure your view resolver.
1. first create spring-dispatcher.xml file.
2. Add view resolver configuration in your xml file.
<beans:property name = "prefix" value = "/WEB-INF/views/" />
<beans:property name = "suffix" value = ".jsp" />
3. place jsp file in views folder under webapp--> WEB-INF.
4. Now view resolver will find jsp at this path " /WEB-INF/views/yoursjspname.jsp ".
Вы должны сначала как минимум отформатировать его должным образом и предоставить структуру проекта.