Не можете понять, как предоставить пользователю все возможности для запуска, остановки и перезапуска программы?

Хорошо, поэтому я пытаюсь создать этот счетчик случайных чисел, который в основном сообщает пользователям, является ли введенное ими число меньше, больше или равно 50, а также дает им возможность запускать, останавливать и перезапускать счетчик случайных чисел "Вот код:

    #include <iostream>


using namespace std;

main() {
        cin >> boolalpha;

        int invalid_answer {0};
        const int const_num {50};
        int random_num {};
        char answer {};
        int keep_going {};

        while (keep_going == 0) {
            while (invalid_answer == 0) {

    //=======================================================================================================================================

                cout << "Enter a random number and we will tell you if it is greater than or less than " << const_num << ": " << endl;
                cin >> random_num;

                if (random_num > const_num) {

                    cout << random_num << " is greater than " << const_num;
                }
                else if (random_num == const_num) {

                    cout << random_num << " is the same as " << const_num << endl;
                }
                else {

                    cout << random_num << " is less than " << const_num << endl;
                }

                cout << "Want to try again? Type \"Y\" or \"N\"";
                cin >> answer;

    //=======================================================================================================================================

                if (answer == 'N') {

                    cout << "Ok then, sorry to see you miss out" << endl;
                    keep_going = 1;
                    }

    //=======================================================================================================================================

                while(answer == 'Y') {

                    cout << "Enter a random number and we will tell you if it is greater than or less than " << const_num << ": " << endl;
                    cin >> random_num;

                    if (random_num > const_num) {

                        cout << random_num << " is greater than " << const_num;
                    }
                    else if (random_num == const_num) {

                        cout << random_num << " is the same as " << const_num << endl;
                    }
                    else {

                        cout << random_num << " is less than " << const_num << endl;
                    }

                    cout << "\nWant to try again? Type \"Y\" or \"N\"";
                    cin >> answer;
                }

    //=======================================================================================================================================

                if (answer != 'Y' || answer != 'N') {
                    invalid_answer = 1;
                    }

    //=======================================================================================================================================

                while (invalid_answer == 1) {
                    cout << "I'm sorry what? Please note that answers are case sensitive. Answer again: ";
                    cin >> answer;

                    if (answer == 'Y') {
                        invalid_answer = 0;
                        }
                    else if (answer == 'N') {
                    cout << "Ok then, sorry to see you miss out" << endl;
                    keep_going = 1;
                    }
            }
            }        
        }

}

Когда я говорю «N» вместо «Нет», я не хочу переделывать средство проверки случайных чисел, оно не меняет keep_going на 1, а просто переходит к одному из других операторов if или while под ним. Поэтому, когда вы вводите «N», он просто выводит либо "Enter a random number and we will tell you if it is greater than or less than " << const_num << ": ", либо "I'm sorry what? Please note that answers are case sensitive. Answer again: ".