Преобразование документа Microsoft Word в PDF с помощью Python

я решил эту проблему и исправил код, следующий

import os
import win32com.client
import re
path = (r'D:\programing\test')
word_file_names = []
word = win32com.client.Dispatch('Word.Application')
for dirpath, dirnames, filenames in os.walk(path):
    for f in filenames:  
        if f.lower().endswith(".docx") :
            new_name = f.replace(".docx", ".pdf")
            in_file =(dirpath + '/'+ f)
            new_file =(dirpath + '/' + new_name)
            doc = word.Documents.Open(in_file)
            doc.SaveAs(new_file, FileFormat = 17)
            doc.Close()
        if f.lower().endswith(".doc"):
            new_name = f.replace(".doc", ".pdf")
            in_file =(dirpath +'/' + f)
            new_file =(dirpath +'/' + new_name)
            doc = word.Documents.Open(in_file)
            doc.SaveAs(new_file, FileFormat = 17)
            doc.Close()
word.Quit()

Вы можете использовать комтипы,

from comtypes.client import CreateObject
import os

folder = "folder path"
wdToPDF = CreateObject("Word.Application")
wdFormatPDF = 17
files = os.listdir(folder)
word_files = [f for f in files if f.endswith((".doc", ".docx"))]
for word_file in word_files:
    word_path = os.path.join(folder, word_file)
    pdf_path = word_path
    if pdf_path[-3:] != 'pdf':
        pdf_path = pdf_path + ".pdf"

    if os.path.exists(pdf_path):
        os.remove(pdf_path)

    pdfCreate = wdToPDF.Documents.Open(word_path)
    pdfCreate.SaveAs(pdf_path, wdFormatPDF)

Это проще:

from docx2pdf import convert

convert(word_path, pdf_path)